If sec theta - tan theta = x/y (0 lt x ...

If `sec theta - tan theta = x/y (0 lt x lt y) and 0^@ lt theta lt 90^@` , then `sin theta ` is equal to

A

`(y^2-x^2)/(x^2+y^2)`

B

`(x^2+y^2)/(y^2-x^2)`

C

`(2xy)/(x^2+y^2)`

D

`(x^2+y^2)/(2xy)`

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The correct Answer is:

A

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