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Angular momentum of a single particle mo...

Angular momentum of a single particle moving with constant speed along circular path :

A

remains same in magnitude but changes in the direction

B

is zero

C

changes in magnitude but remains same in the direction

D

remains same in magnitude and direction

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The correct Answer is:
To solve the problem of finding the angular momentum of a single particle moving with constant speed along a circular path, we can follow these steps: ### Step 1: Understand the Definition of Angular Momentum Angular momentum (L) of a particle is defined as the product of its moment of inertia (I) and its angular velocity (ω). The formula is given by: \[ L = I \cdot \omega \] ### Step 2: Identify the Moment of Inertia For a point mass (m) moving in a circular path of radius (R), the moment of inertia (I) is given by: \[ I = mR^2 \] ### Step 3: Relate Angular Velocity to Linear Velocity The angular velocity (ω) can be related to the linear velocity (v) of the particle by the formula: \[ \omega = \frac{v}{R} \] ### Step 4: Substitute Values into the Angular Momentum Formula Now we can substitute the expressions for I and ω into the angular momentum formula: \[ L = I \cdot \omega = (mR^2) \cdot \left(\frac{v}{R}\right) \] ### Step 5: Simplify the Expression By simplifying the expression, we get: \[ L = mR^2 \cdot \frac{v}{R} = m v R \] ### Step 6: Analyze the Magnitude and Direction Since the mass (m), speed (v), and radius (R) of the particle are constant, the magnitude of angular momentum (L) remains constant. ### Step 7: Determine the Direction of Angular Momentum The direction of angular momentum is determined by the right-hand rule. If the particle is moving in a circular path, the direction of angular momentum is along the axis perpendicular to the plane of rotation. If the motion is counterclockwise, the direction is positive along the z-axis (k-cap). If it is clockwise, the direction is negative along the z-axis (-k-cap). ### Conclusion In conclusion, the angular momentum of a single particle moving with constant speed along a circular path remains constant in both magnitude and direction. ### Final Answer The correct option is that the angular momentum remains the same in both magnitude and direction. ---
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