298 K पर निम्नलिखित सेल के लिए `Pt|H_(2)(1" bar")|H^(+)(1M)||M^(4+),M^(2+)|Pt`
जब `([M^(2)])/([M^(4)])=10^(x)` तब `E_("cell")=0.092 V`
यदि `E_(M^(4+)//M^(2+))^(@)=0.151V` तथा `(2.303RT)/(F)=0.059V`. तब x का मान है

Options

A. `-2`
B. `-1`
C. 1
D. 2

Answer

D

Explanation

एनोड : `H_(2) (s) to 2H^(+) + 2e^(-)`
कैथोड: `Mn^(4+) + 2e^(-) to Mn^(2+)`
__________________________
`Mn^(4+) + H^(2) to Mn^(2+) + 2H^(+)`
`E = E^(@) = 0.151 - 0.059/2 log_(10)(([Mn^(2+)][H^(+)]^(2))/([Mn^(4+)][P_(H_(2))]))`
`0.092 =0.151 - 0.059/2 log_(10)(10^(x))`
`x=2`