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How many geometrical isomers of this com...


How many geometrical isomers of this compound are possible ?

A

2

B

3

C

4

D

6

Text Solution

Verified by Experts

The correct Answer is:
B
Total geometrical isomers
` = 2^(n - 1) + 2^(n-1) p = n/2`
`= 2^1 + 2^@`
`= 3`
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