Ethyl acetoacetate when reacts with one mole methyl magnesium iodide then product of reaction will be :

Options

A. `CH_(3)-overset(O)overset(||)(C)-CH_(2)-overset(O)overset(||)(C)-CH_(3)`
B. `{:(" "O^(ɵ)Moverset(o+)(g)Br" "O),(" |"" ||"),(CH_(3)-C-CH_(2)-C-CH_(3)),(" |"),(" "CH_(3)):}`
C. `CH_(3)-overset(O)overset(||)(C)-underset(overset(o+)(M)gBr)overset(ɵ)(CH_(2))-CO_(2)Et`
D. `CH_(2)^(-) -overset(O)overset(||)(C)-CH_(2)-CO_(2)Et`

Answer

C

Explanation

(because of active methylene group acid-base take place).