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CH(3)CH(2)CH(OH)CH(CH(3))(2)+CH(3)COCl o...

`CH_(3)CH_(2)CH(OH)CH(CH_(3))_(2)+CH_(3)COCl overset("base")to CH_(3)CH_(2)CH(OCOCH_(3))CH(CH_(3))_(2)+HCl` In the above reaction, if the reactant alcohol is a pure R-isomer the product would.

A

have configuration inverted at the chiral atom

B

be a racemic mixture

C

have the same configuration at the chiral atom

D

be optically inactive

Text Solution

Verified by Experts

The correct Answer is:
C
have the same configuration at the chiral atom
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