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Hoffmann bromamide reaction involves con...

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain.
`R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3)`
Mechanism of the reaction is :

Product (A) :

A

`Ph-NH_(2)`

B

`Ph-CH_(2)-NH_(2)`

C

`Ph-NH-CH_(3)`

D

Text Solution

Verified by Experts

The correct Answer is:
A

`PhCONH_(2) underset(KOH)overset(Br_(2))to PhNH_(2)`
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Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Which of the following will not give Hoffmann bromamide reaction.

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Number of moles of NaOH consumed in above reaction.

In the following reaction , product 'P' is : R-overset(O)overset(||)(C)-Clunderset(Pd-BaSO_(4))overset(H_(2))toP

R-overset(O)overset(||)C-NH_(2)+xNaOH +Br_(2) to R-NH_(2)+2NaBr +Na_(2)CO_(3) +H_(2)O Number of moles of NaOH used in above Hoffmann bromamide reaction is :

CH_(3)CH_(2)-overset(O)overset(||)(C)-CH_(3)underset(HCl)overset(NaNO_(2))to , Major product of this reaction is :

H - C = C- H underset(H_2SO_4) overset(HgSO_4)to (A) underset((2) H_3O^(o+)) overset((1) NH_3 + HCN)to(B) , Product (B) of given reaction is :

CH_3 - CH=CH_2 underset("(low conc.)")overset(Br_2 //hv ) to (A) , Product (A) of the reaction is :

CH_(3)-overset(O)overset(||)C-O-CH_(2)-CH_(3)+H-O^(-) to (O= O^(18)) One of the product of the reaction is :

The major product in the reaction, CH_(3)CH_(2)NH_(2)+Cl-overset(O)overset(||)C-CH_(3) is

CH_(3)CH_(2)C-=CH underset("liq. " NH_(3))overset(NaNH_(2))rarr I Product (K) of the above reaction is :

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