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Hoffmann bromamide reaction involves con...

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain.
`R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3)`
Mechanism of the reaction is :

Which of the following will not give Hoffmann bromamide reaction.

A

`CH_(3)-overset(O)overset(||)C-NH_(2)`

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
D

`2^(@)` amide do not give Hoffmann.
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Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Product (A) :

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Product (A) is :

Hoffmann bromamide reaction involves conversion of a carboxylic acid amide into an amine with a loss of a carbon atom on treatment with aqueous sodium hypobromite. Thus Hoffmann result in shortening of a carbon chain. R-overset(O)overset(||)C-NH_(2) underset(NaOH) overset(Br_(2))to R -NH_(2) +NaBr +Na_(2)CO_(3) Mechanism of the reaction is : Number of moles of NaOH consumed in above reaction.

In the following reaction , product 'P' is : R-overset(O)overset(||)(C)-Clunderset(Pd-BaSO_(4))overset(H_(2))toP

R-overset(O)overset(||)C-NH_(2)+xNaOH +Br_(2) to R-NH_(2)+2NaBr +Na_(2)CO_(3) +H_(2)O Number of moles of NaOH used in above Hoffmann bromamide reaction is :

H - C = C- H underset(H_2SO_4) overset(HgSO_4)to (A) underset((2) H_3O^(o+)) overset((1) NH_3 + HCN)to(B) , Product (B) of given reaction is :

The major product in the reaction, CH_(3)CH_(2)NH_(2)+Cl-overset(O)overset(||)C-CH_(3) is

CH_(3)CH_(2)C-=CH underset("liq. " NH_(3))overset(NaNH_(2))rarr I Product (K) of the above reaction is :

CH_3 - overset(CH_3)overset(|)underset(OH)underset(|)C-CH_3 overset(Na_2Cr_2O_7)underset("cool") rarr (P) , product (P) in the reaction is :

Which product do you expect from the reaction ? CH_(3) - overset(CH_(3))overset(|)(C) = CH_(2) underset((ii)H_(2)O_(2),OH)overset((i) (BH_(3))_(2))rarr

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