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Consider the given reaction for preparation of alkyne. (Fritsch reaction). Anti group will migrate because of less steric hindrance. Product (A) is : (C^(**)=C^(14))
CH_3 - underset(CH_3)underset(|) overset(CH_3) overset(|) (CH) overset(KmnO_4)to (A ) underset(Delta)overset(H^+)to (B ) underset(ROOR)overset(HBr)to (C ) Product (C) in the above reactions is :
, Product ( C) of the reaction is :
, Product ( C) of the reaction is :
, Product (C) of the reaction is :
End product ( C) in above reaction is :
Ph-overset(O)overset(||)(C)-CH_(3)underset(HCl)overset(NaNO_(2))to(A)underset("heat")overset(AC_(2)O)to(B)overset(H_(3)O^(+))to(C) Product ( C) of the above reaction is :
Succinic acid overset(Delta)rarr (A) overset(NH_2)underset(Delta) rarr (B) overset(Br_2)underset(KOH)rarr(C) , "Product (C) will be :"
Two benzyne intermediates are likely to be formed equally. Reaction with amide ion can occur in two different directions with each benzyne, giving three possible products. They are formed in a 1:2:1 ratio. Asterisk (*) refers to ""^14 C . Product major, product (A) is :
MS CHOUHAN-AROMATIC COMPOUNDS -LEVEL-2 (SUBJECTIVE PROBLEMS)