A mixture if hydrogen and oxygeb hs volume `2000cm^((3)`, temperature 300K, pressure 100kPa and mass 0.76g.Calculate the masses of hydrogen and oxygen in the mixture.

Explanation

Suppose there are `n_(1)` moles of hydrogen and `n_(2)` moles of oxygen in the mixture. The pressyre of the mixture will be
`p=(n_(1)RT)/(V)+n_(2)RT/(V)=(n_(1)+n_(2))(RT)/(V)`
or, `100xx10^(3)Pa=(n_(1)+n_(2))(8.3JK^(-1)mol^(-1)(300K))/(2000xx10^(-6)m^(-3))
or, n_(1)+n_(2)=0.08mol`. ...(i)
The mass of the mixture is
`n_(1)xx2g mol^(-1)+n_(2)xx32g mol^(-1)=0.76g`
or, `n_(1)+16n_(2)=0.38mol`. ...(ii)
from (i) and(ii),
`n_(1)=0.06 mol and n_(2)=0.02 mol`.
the mass of hydrogen = `0.06xx2g =0.12g` and the mass of oxygen `=0.02xx32g=0.64g`.