An ideal gas has pressure `p_(0)`, volume `V_(0)` and temperature `T_(0)`. It is taken an isochoric process till its pressure is doubled. It is now isothermally expanded to get the original pressure. Finally , the gas is isobarically compressed to its original volume `V_(0)`. (a) Show the process on a p-V diagram. (b) What is the tempertaure in the isothermal part of the process? (c) What is the volume at the end of the isothermal part of the process?

Explanation

The process is shown in a `p-V` diagram in figure. The process starts from `A` and goes through `ABCD`
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(b) Applying `pV = nRT at A and B`
`p_(0)V_(0)=nRT_(0)`
and `(2p_(0)V_(0)=n RT_(B)`
thus, `T_(B) = 2 T_(0)`
Thus is the temperatrue in the isothermal parts BC,
(c) As the process `BC` is isothermal `T_(C) = T_(B) = 2T_(0)` applying `pV = nRT` at A and C
`p_(0)V_(0)=nRT_(0)`
and `p_(0)V_(c)=nRT(2T_(0))`
or, `V_(c)=2V_(0)`.