A gas cylinder has walls that can bear a maximum pressure of `1.0xx10^(6)`Pa. It contains a gas at `8.0xx10^(5)`Pa and 300K. The cylinder is steadily heated. Neglecting any change in the volume calculate the temperature at which the cylinder will break.

Explanation

Given
`P_max = 1.0 xx 10^6Pa ,`
` P_0 = 8.0 xx 10^5Pa,`
` T_0 = 300K`
` Volume is constant(Given)
So Gas law,
` (P_1 V_1)/(T_1)= (P_2 V_2)/(T_2) (:. V_1=V_2)`
` (P_1)/(T_1) =(P_2)/(T_2)`
` or T_2 = (P_max xx T_0)/P_0`
` =(1.0 xx 10^6 xx 300)/(8.0 xx 10^5)`
` = 375K`