2g of hydrogen is sealed in a vessel of volume `0.02m^(3)`and is maintained at 300K. Calculate the pressure in the vessel.

Explanation

Given that:
` n= 1 mole,` V= 0.02 m^3`
` T= 300K, ` R=8.3 `
From the formula
` PV= nRT `
`P=(nRT)/V =(1 xx 8.3 xx 300)/(0.02)`
` P=1.24 xx 10 ^5Pa `