Find the rms speed of hydrogen gas at 300K. Find the temperature at which the rms speed is double the speed calculated in the previous part.

Explanation

r.m.s velocity of Hydrogen molecule =?
` T = 300K, R= 8.3 `
` M= 2g =2 xx 10^-3kg `
` C= (sqrt (3RT))/(sqrt M)`
` = (sqrt (3 xx 8.3 xx 300))/ (sqrt (2 xx 10^-3))`
`=1932.6 m/s`
` = ~ 1930 m/s `
`Let the temperature at the `
` C= 2 xx 1932.6 is T'`
`Then 2 xx 1932.6 =(sqrt( 3 xx 8.3 xx T'))/(sqrt(2 xx 10^-3))`
` rArr (2 xx 1932.6)^2=(3 xx 8.3 xx T')/(2 xx 10^-3)`
` rArr (((2 xx 1932.6)^2) xx 2 xx 10^3)/(3 xx 8.3)=T'`
` rArr T'=1199.98`
` ~~1200K`