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One mole of an ideal gas undergoes a pro...

One mole of an ideal gas undergoes a process
` p=(p_(0))/(1+((V)/(V_(0)))^(2))`
where `p_(0)`and `V_(0)` are constants. Find temperature of the gas when `V=V_(0)`.

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Here, `P= (P_0/ 1+((V/V_0)^2) )`
` rArr nRT/ V = (P_0 / 1+((V/V_0)^2))`
` [PV= nRT according to ideal gas equation]`
` rArr RT/V = (P_0/ (1+ ((V/V_0)^2))) ` [ Since n = 1 mole]`
` rArr RT/V_0 = (P_0/ 1+ ((V/V_0)^2)) [ at V = V_0]`
` rArr (P_0)(V_0) = RT(1+1)`
` rArr (P_0)(V_0) = RT xx 2 `
` T = ((P_0)(V_0)/2R)`
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