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Pure water vapour is trapped in a vessel...

Pure water vapour is trapped in a vessel of volume `10cm^(3)`. The relative humidity is 40%. The vapour is compressed slowly and isothermally.find the volume of the vapour at which it will start condendsing.

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`(R_H) = (VP/SVP)`
The point where the vapour start
condensing,
` VP= SVP `
` We know ((P_1)(V_1)=(P_2)(V_2))`
` (R_H) xx SVP xx 10 = SVP xx (V_2)`
rArr (V_2) = 10R_H`
` = 10 xx 0.4 `
` = 4 cm^3.`
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