Test dimensionally if the formula `t= 2 pi sqrt(m/(F/x))` may be corect where t is time period, F is force and x is distance.

Explanation

The dimension of force is `MLT^-2` Thus, the dimension of the right hand side is
` sqrt(M)/(MLT^(-2)//L) = sqrt((1)/(T^(-2)) =T`
The ledt fhnd side is time period and hence the dimension is T. The dimensions of both sides are equl and hence the formula may be correct.