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Test dimensionally if the v^2=u^2+2ax ma...

Test dimensionally if the `v^2=u^2+2ax` may be correct.

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There are three terms in this equation `v^2,u^2` and 2ax. The equationmay be correct if the dimensions of these three terms are equal.
`[v^2]=(L/T)^2=L^2T^-2,`
` [u^2]=(L/T)^2=L^2T^-2`,
` and [2ax]=[a][x] =(L/T^2)L=L^2T^-2`
Thus, the equation may be correct.
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