Evaluate `int^6_3`(2x^2+3x+5)dx`.

Explanation

`int(2x^2+3x+5)dx`
` =int 2x^2dx+int 3xx+int 5 dx`
`=2int x^2dx+3intx dx+5 int x^0dx`
` 2x^3/3+3x^2/2+tx^1/1`
` =2/3 x^3+3/2 x^2+5x`
Thus, `int^6_3(2x^2+3x+5)dx=[2/3x^3+3/2x^2+5x]^6_3`
`2/3(216-27)+3/2(36-9)+5(6-3)`
`=126+40.5+15=18.15`.