A table clock has its minute hand 4.0 cm long. Find the average velocity of the tip of the minute hand a. between 6.00 a.m. to 6.30 a.m.

Explanation

Ast 6.00 the tip of the minute hand is at 12 mark and at 6.30 a.m. or 6.30 p.m. it is `180^0` away. Thus, the straight line distance between the initial and fiN/Al position of the tip is equal to the diameter of the clock.
Displacement `=2R=2xx4.0cm=8.0cm`.
The displacement is from the 12 mark to the 6 mark on the clock panel. This is also the direction of the average velocity in both cases.
The time taken from 6.00 a.m. to 6.30 a.m. is 30 minutes= 1800s. The average velocity is
`v_(av)=Displacement/time =(8.0cm)/(1800s)= 4.4x10^-3 cm/s`. b. The time taken from 6.00 a.m.to 6.30 p.m. is 12 hours and 30 minutes = 45000s. The averasge velocity is ltbr. `v_(av)=Displacement/time =(8.0 cm)/(45000s)= 1.8xx10^04 cm/s`.