A ball is thrown vertically upward at a speed of 10 m/s. When it has reached one half of its maximum height. How high does the ball rise? (g=10ms^(-2)`)

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take g=10 m//s^2 .

A ball is thrown vertically upwards with the speed of 19.6 ms^(-1) from the top of building and reaches the earth in 6 s. Find the height of the building .

A particle is thrown vertically upwards its velocity at half of the height is 10 m/s then the maximum height attained by it is ( g= 10 m//s^2)

A ball is projected vertically up with a speed of 50 m/s. Find the maximum height , the time to reach the maximum height, and the speed at the maximum height (g=10 m//s^(2)) (AS_(1))

A ball is thrown at a speed of 40 m/s at an angle of 60^0 with the horizontal. Find a. the maximum height reached and b. the range of te ball. Take g=10 m/s^2 .

A ball thrown vertically upwards with a speed of 19.6ms^(-1) from the top of a tower returns to the Earth in 6s. Find the height of the tower. (g=9.8m//s^(2))

(i) Write down the equation of a freely falling body under gravity. (ii) A ball is thrown vertically upwards with the speed of 19.6ms^(-1) from the top of a building and reaches the earth in 6s . Find the height of the building.