A projectile is fired at an angle of `45 ^ { \circ }` with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is

Explanation

Here u= 15 m/s, ` theta = 60^0, g= 9.8 m/s^2`
Horizontal range,
`x= (u^2 sin 2theta)/g`
= ((15)2 sin (2x`60^@`)/g`
` 19.88m`
IN the first case the wall is 5 m away from projection point, so it is in the horizontal range of projectile. So the ball will hit he wall. ltbrlt IN the second case (22 m away) wall is notk within the horizontal range. So the ball would not hit the wall.