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The magnitude of static frictional force...

The magnitude of static frictional force `f_s` lies between

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The correct Answer is:
B
The limb exerts a normal force 48 N and frictional force of 20 N.


Resultant magnitude of the force `R= sqrt( (48^2+20^2))`
` = sqrt(2304+400) `
` sqrt(2704) = 52 N`.
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