A heavy particle of mass 0.50 kg is hanging from a string fixed with the roof. Find the force exerted by the string on the particle. Take `g = 9.8 m/s^2`
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Explanation

The forces acting on the particle are
a. pull of the earth `0.50 kg xx 9.8 m/s^2=4.9N` vertically downward
b. pull of the string, T (Tension force) acting vertically upward.
The particle is at rest with respect to the earth (which we assume to be an inertial frame). Hence, the sum of the forces should be zero. Therefore, T is 4.9 N acting vertically upward.