If x = a cos t is the displacement in time t then, acceleration is :

If x, v & a denote the displacement , the velocity & acceleration of a particle executing simple harmonic motion of time period T, then which of the following does not change with time .

The angular displacement theta radians of a fly wheel varies with time t seconds and follow the equation theta = 9t^(2) - 2t^(3) . Determine the angular velocity and acceleration of the fly wheel when time t =1 seconds and (ii) The time when the angular acceleration is zero.

A body oscillates with SHM according to the equation (in SI units), x = 5 cos [2pi t + pi//4] . At t = 1.5 s, calculate the (a) displacement, (b) speed and (c) acceleration of the body.

Displacement (y) of the particle is given by: y = 2 t + t ^ { 2 } - 2 t ^ { 3 } . Then, the velocity of the particle when acceleration is zero is

A body oscillates with SHM along with x - axis. Its displacement varies with time according to the equation x=(4.00m)cos(pi_(t)^(+)(pi)/(4)) calculate at t = 1.00s : (a) displacement (b) velocity (c) acceleration (d) Also calculate the maximum speed and maximum acceleration and (e) phase at t = 2.00s.

Check The correctness of the following equation using dimensional analysis. Make a comment on it. S = ut + 1//2 "at"^(2) where s is the displacement, u is the initial velocily, t is the time and a is the acceleration produced,

A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6s. At t=0 it is at position x=5 cm going towards positive x-direction. Write the equation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t=4s.

The x and y coordination of the particle at any time are x=5t - 2t^2 and y =10 t respectively , where x and y are in metres and t in seconds . The acceleration of the particle at t=2s is: