Both the springs shown in figure are untretched. If the block is displaced by a distance x and released, what will be the initial acceleration?

Explanation

Given, `x=20 cm= 0.2 m,`
`k=15 N/m, m=0.3 kg`
` Acceleration, a= F/m = (-kx)/m= (-15(0.2))/0.3`
= - 3/0.3 = - 10 m/s^2`
(deceleration),
So, the acceleration is 10 m/s^2 opposite to the direction of motion.