A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 40 m with an acceleration of `0.5 m/s^2` find the work done by the man on the block during the motion.

Answer

D

Explanation

`m_b=2kg, s=40m, a=0.5m/sec^2`
so, force aplied by the man on the box,
`F=m_ba`
`=2xx(0.5)`
`=1N`
`omega=F.S`
`=1xx40`
=40J