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A block of mass 250 g slides down an inc...

A block of mass 250 g slides down an incline of inclination `37^0` with a uniform speed. Find the work done against the friction as the block slides through 1.0 m.

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The correct Answer is:
A
`m_b=250g, theta=37^0, S=`m`
frictioN/Al force ,`f=muR`
`mgsinthet=muR`……i
mg costheta=R`……..ii

So, work done against `muR`
`=mu RS sintheta`
`=mg 3/5 S`
`=250xx9.8xx3/5xx1=1.5`
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