A block of weight 100 N is slowly slide up on a smooth incline of inclination `37^0` by as person. Calculate the work done by the person in moving the block through a distance of 2.0 m, if the driving force is a. parallel to the incline and b. in the horizontal direction.

Answer

A, B

Explanation

`W=100N, theta=37^0, s=2m`
Force, `F=mgsin37^0`
`=100xx3/5=60N`
So, work done when the force is parallel to incline,
`w=Fscostheta`
`=60xx2xxcos0^0=120'J`

`In /_\ABC, AB=2m`
AC=h`
`s sin 37^0`
`=1.2m`
`:.` Work done when the force in horizontal direction
`w=mgh`
`=100xx1.2=120J`