A particle of mass m moves on a straight line with its velocity varying with the distance travelled according to the equation `v=asqrtx`, where a is a constant. Find the total work done by all the forces during a displacement from `x=0 to x=d`.

Answer

A, B, D

Explanation

Given
`v=asqrt(x(uniformly accelerated motion))`
dispacement `s=d-0=d`
`putting x=0,v_1=0, v_2=asqrtd`
`a=(v_2^2-v_1^2)/(2S)=(a^2d)/(2d)=a^2/2`
forfe `F=ma=(ma^2)/2`
Work done `w=Fscostheta`
`=(ma^2)/2xxd=(ma^2d)/2`