A uniform rod of mass 300 g and length 50 cm rotates at a uniform angular speed of 2 rad/s about an axis perpendicular to the rod through an end. Calculate a. the angular momentum of the rod about the axis of rotation b. its kinetic energy.

Answer

A, B, C

Explanation

A uniform of rod mass 300 gm and length =50 cm rotates wilth a uniform angular velocity =2 rad/s abut an axis `_|_` to te rod through an end.
a. `L=Iomega`
`I at the end =(mL^2)/3=({0.3xx(0.5)^2})/3`
`=((.3xx0.25))/3`
`=0.075/3=0.025kg-m^2`
Therefore angular momentum about that point
`=0.025xx2`
`-=0.05kg-m^2/s`
b. Sped ofthe centre of rod
`V=omegar=2xx(50/2)`
`=50 cm/s=0.5m/s`
c. It kinetic energy
c. `1/2Iomega^2=(1/2)xx0.025xx2^2`
`=0.05joule