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The resultant force acting on a particle executing simple harmonic motion is 4N when it is 5cm away from the centre of oscillation. Find the spring constant.

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The simple harmonic motion is defilned as ltbr. `F=-kx`
The spring constant is `k=|F/x|`
`=(4N)/(5cm)=(4N)/(5xx10^-2m)=80Nm^-1`
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HC VERMA-SIMPLE HARMONIC MOTION-Exercises
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  2. A particle executes simple harmonic motion with an amplitude of 10 cm ...

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  3. The position velocity and acceleration of a particle executing simple ...

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  4. A particle executes simple harmonic motion with an amplitude of 10 cm....

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  5. The maximum speed and acceleration of a particle executing simple harm...

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  7. The equation of motion of a particle started at t=0 is given by x=5sin...

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  8. Consider a particle moving in simple harmonic motion according to the ...

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  10. The pendulum of a clock is replaced by a spring mass system with the s...

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  11. A block suspended from a vertical spring is in equilibrium. Show that ...

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  12. A block of mass 0.5 kg hanging from a vertical spring executes simple ...

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  13. A body of mass 2 kg suspended through a vertical spring executes simpl...

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  14. A spring stores 5J of energy when stretched by 25 cm. It is kept verti...

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  15. A small block of mass m is kept on a bigger block of mass M which is a...

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  16. The block of mass m1 shown in figure is fastened to the spring and the...

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  17. In figure, k = 100 N//m, M = 1kg and F = 10 N (a) Find the compre...

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  18. Find the time period of the oscillation of mass m in figure a,b,c wha...

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  19. The spring shown in figure is unstretched when a man starts pulling on...

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  20. A particle of mass m is attached to three springs A,B and C of equal f...

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  21. Repeat the previous exercise if the angle between each pair of springs...

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