A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then find its time period in seconds.

A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6s. At t=0 it is at position x=5 cm going towards positive x-direction. Write the equation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t=4s.

A particle executes simple harmonic motion with a frequency. (f). The frequency with which its kinetic energy oscillates is.

A partical executes simple harmonic oscillation with an amplitude a. the period of oscillation is T The minimum time taken by the partical to travel half of the amplitude from the equilibrium position is:

For a particle executing simple harmonic motion, the acceleration is proportional to

A particle executes simple harmonic motion of amplitude A along the X-axis. At t=0 the position of the particle is x=A/2 and it moves along the positive x-direction. Find the phase constant delta if the equation is written as x=Asin(omegat+delta)

A particle of mass 40 g executes a simple harmonic motion of amplitude 2.0 cm. If the time period is 0.20 s, find the total mechanical energy of the system.

The resultant force acting on a particle executing simple harmonic motion is 4N when it is 5cm away from the centre of oscillation. Find the spring constant.