A block of mass 0.5 kg hanging from a vertical spring executes simple harmonic motion of amplitude 0.1 m and time period 0.314s. Find the maximum fore exerted by the spring on the blockl.

Answer

`=25N`

Explanation

`x=r=0.1, T=0.314 sec, m=0.5kg `
Total force exerted on the block =Weight of the block +spring force

`T=2pi(sqrt(m/k))`
`rarr 0.314=2pi(sqrt(0.5/k))`
`rarr k=200N/m`
`:.` Maximum force =`F+weight =20+5`
`=25N`