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Find the elastic potential energy stored...

Find the elastic potential energy stored in each spring shown in figure, when the block is in equilibrium. Also find the time period of vertical oscillation of the block.

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The correct Answer is:
`=2pi sqrt(M(1/k_1+1/k_2+1/k_3))`
`PE_1=(m^2g^2)/(2k_1)`
`PE_2=(m^2g^2)/(2k_2)`
`PE_3=(m^2g^2)/(2k_3)`

`k_1, k_2, k_3` are in series
`=1/k=1/k_1+1/k_2+1/k_3`
`rarr K=(k_1k_2k_3)/(k_1k_2+k_2k_3+k_3k_1)`
time period
`T=2pisqrt(m/k)`
`=2pi sqrt(M(1/k_1+1/k_2+1/k_3))`
Now force =weight =mg
:. At `k_1` spring
`x_1=(mg)/k_1`
similarly `x_2=(mg)/k_2`
and `x_3=(mg)/k_3`
`:. PE_1=1/2k_1x_1^2`
`=1/2k_1((Mg)/K_1)^2`
`=1/2k_1(m^2g^2)/k_1^2`
`=1/2 (m^2g^2)/k_1=(m^2g^2)/(2k_1)`
similarly `PE_2=(m^2g^2)/(2k_2)`
and `PE_3=(m^2g^2)/(2k_3)`
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