State the laws of simple pendulum.

Answer

lenght of the pendulum is 1m.

Explanation

From the equation
`theta=(pi/0)sin[pi(sec^-1)t]`
`:. omega=pisec^-1`
(comparing with the eqution of SHM)
`(2pi)/T=pi`
`rarr T=2sec`
We know that `t=2pi sqrt((l/g))`
`rarr 2=2pisqrt((l/g))`
`rarr 1=pisqrt((l/g))`
`rarr l=m`
`:.` lenght of the pendulum is 1m.