A pendulum clock giving correct time at a place where `g=9.800 ms^-2 is taken to another place where it loses 2 seconds during 24 hours. Find the value of g at this new place.

Answer

`=9.795m/s^2`

Explanation

For the pendulum
`T_1/T_2=sqrt((g_2/g_1))`
Given that `T_2=2sec, g_1=9.8m/s^2`
`T_1=(24xx3600)/((24xx360xx-24)/2)`
`=2xx3600/3599`
now `(g_2/g_1)=(T_1/T_2)^2`
`:. g_2=(9.8)(3599/3600)^2`
`=9.795m/s^2`