The maximum tension in the string of an oscillating pendulum is double of the minimum tension. Find the angular amplitude.

Answer

A, C, D

Explanation

The tension in the pendulum is maximum at the mea position and minimum on th extreme postion.
`Here `1/2mv^2-0=mgl(1-costheta)`
`v^2=2gl(1-costheta)` ……….1
`-Now, T_(ma)=mg+2mg(1-costheta)`
`[T=mg+(mv^2/l)]`
`Again T_(min)=mgcostheta`
According to question
`T_(max)=2Tmin`
`rarr mg+2mg-2mgcostheta=2mgcostheta`
`rarr 3mg=4mgcostheta`
`costheta=3/4`
`rarr thetas=cos^-1 3/4`