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In figure the upper wire is made of stee...

In figure the upper wire is made of steel and the lower of copper. The wires have equal cross section. Find the ratio of the longitudinal strains developed in the two wires.

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The correct Answer is:
A, C, D
`rarr ((DeltaL)/L_(steel))F/(AY_(Steel))`
`rarr ((DeltaL)`/`L_(cu))=F/(AY_(cu))`

Strain in steel wire /Strain in copper wire`=F/(AY_(Steel))+(AY_(cu))/F`
`(A_cu)=A_(Steel)`
`Y_(cu)/Y_(Steel)=13/20=0.65`
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