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Two person pull a rope towards themselves. Each person exerts a force of 100 N on the rope. Find the Young modulus of the material of the rope if it extends in length by 1 cm. Original length of the rope=2 m and the area of cross section =`2 cm^2`.

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The correct Answer is:
A, B
`F=100N`
`L=2m, `
`/_\\l=0.01m`,
`A=2xx10^-4`
`Y=F/AxxL/(/_\\L)`
`=100/(2xx10^-4)xx1/0.001`
`=1xx10^8N/m^2`
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