Find the surface energy of water kept in...

Find the surface energy of water kept in a cylindrical vessel of radius 6.0 cm. Surface tension of water `=0.075Jm^-2`.

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The correct Answer is:

A, D

`T`=0.075J/`m^2`, r=6.0cm=0.06m,
A=`pi``r^2`=`pi``(0.06)^2`
so, surface energy
`=(0.075)3.140(0.06)^2=8.510^-4J``

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