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Consider an ice cube of edge 1.0 cm kept...

Consider an ice cube of edge 1.0 cm kept in a gravity-free hall. Find the surface area of the water when the ice melts. Neglect the difference in densities of ice and water.

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In the absence of gravilty the water which form due to melting of ice tens to acquire spereical surface.
so, `6a^3=(4/3)pir^3`
`rarr r=[(18a^3)/(4pi)]^(1/3)`
`So, surface area =4pir^2`
`=4pi[(18a^3)/(4pi)]^(2/3)`
`=(36pi)^(1/3)cm^2`
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