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In a Young's double slit experiment lamd...

In a Young's double slit experiment `lamda= 500nm, d=1.0 mm andD=1.0m`. Find the minimum distance from the central maximum for which the intensity is half of the maximum intensity.

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The correct Answer is:
A, B, D
Given that D=1m,
d=1mm=10^I-3m
`l=500nm=5xx10^-7m`
for intensity to be half the maximum intensity
`y=(lamdaD)/(4d)`
`rarr y=(5xx10^-7xx1)/(4xx10^-3)`
`=1.25xx0^-4m`
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