Light of wavelength 560 nm goes through a pinhole of diameter 0.20 mm and falls on a wall at a distance of 2.00 m. What will be the radius of the central bright spot formed on the wall ?

Answer

A, C

Explanation

`lamda=560nm`
`=560xx10^-9m`
`d=0.20mm`
`d0.20mm`
`=2xx10^-4m, D=2m`
`Since R=1.22(lamdaD)/d`
=1.22xx(560xx10^-9xx2)/(2xx10^I-4)`
`=6.832xx10^-3M`
`=0.683cm`
So, diameter =2R=1.37cm