Find the size of the image formed in the situation shown in figure.

Explanation

Here u=-40cm, R=-20cm, `mu_1=1, mu_2=1.33. We have`
`mu_2/v-mu_1/u=(mu_2-mu_1)/R`
`or, 1.33/v-1/(-40cm)=1.33/(-20cm)`
or, `1.33/v=-1/(40cm)-0.3./(20cm)`
`or v=-32cm`
The magnification is
`m=h_2/h_1=(mu_1v)/(mu_2u)`
`or h_2/(1.0cm)=(-32cm)/(1.33x(-40cm)`
or `h_2=+0.6cm`
The image is erect.