One end of a horizontal cylindrical glass rod `(mu=1.5)` of radius 5.0 cm is rounded in the shape of a hemisphere. An object 0.5 mm high is placed perpendicular to the axis of the rod at a difference of 20.0 cm from the rounded edge. Locate the image of the object and find its height.

Explanation

Taking the origin at the vertex `u=-20.0 cm and R=5.0 cm`
We have `mu_2/v-mu_1/u=(mu_2-mu_1)/R`
or `1.5/v=1/(-20.0cm)+0.5/(5.0cm)=1/(20cm)`
or, `v=30cm`