A sound wave of wavelength 40 cm travels in air. If the difference between the maximum and minimum pressures at a given point is `1.0xx10^-3Nm^-2`, find the amplitude of vibration of the particle o the medium. The bulk modulus of air is `1.4xx10^5Nm^-2`.

Explanation

The pressure amplitude is
`p_0=(1.0xx10^-3xxNm^-2)/2=0.5x10^-2Nm^-2`
`p_0=Bks_0`
or `s_0=p_0/(Bk)=(p_0lamda)/(2piB)`
`=0.5xx10^-3Nm^-2xx(40xx10^-2m))/((2xx3.14xx1.4xx10^5Nm^-2)`
`=2.2xx10^-10m`.