A source and a detector move away from each other, each with a speed of `10 ms^-1` with respect to the ground with no wind. If the detector detects a frequency 1950 Hz of the sound coming from the source, what is the original frequency of the source? Speed of sound in air `=340 ms^-1`.

Explanation

If the origiN/Al frequency of the source is v, the apparent frequency heard by the observer is
`v'=(v-u_0)/(v+u_s)`
Where `u_0` is the speed of the observer going away fro the source and `u_s` is the speed of the source going away from the observer. By the question
`1950Hz=(340-10)/(340+10)v`
`or, v=35/33xx1950Hz=2070Hz`.