If the sound level in a room is increased from 50 dB to 60 dB, by what factor is the pressure amplitude increased ?

Answer

A

Explanation

`beta_1=50dB, beta_2=60dB,`
I_1=10^-7W/m^2, I_2=10^-6W/m^2`
`[because beta=10log_10(I/I_0)`
where `I_0=10^-12W/m^2]`
Again, `I_2/I_1=(p_2/p_1)^2=(10^-6/10^-7)=10`
`(where p=pressure amplitude)
`:.(p_2/p_1)^2=10`
`rarr P_2/P_1=sqrt10`