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A piston is fitted in a cylindrical tube of small cross section with the other end of the tube open. The tube resonates with a tuning fork of frequency 512 Hz. The piston is gradually pulled out of the tube and it is found that a second resonance occurs when the piston is pulled out through a distance of 32.0 cm. Calculate the speed of sound in the air of the tube.

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The correct Answer is:
A, B, C
Let the piston resoN/Aes at length `I_1 and I_2`
Here `I=32cm, v=?, n=512 Hz`
`Now, v=52xx0.64=328m/s`
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